//(C) 2017 Andrei Cotor. All rights reserved.
#include<fstream>
#include<bitset>
#include <stdio.h>
#include <ctype.h>
using namespace std;

class InParser {
private:
    FILE *fin;
    char *buff;
    int sp;

    char read_ch() {
        ++sp;
        if (sp == 4096) {
            sp = 0;
            fread(buff, 1, 4096, fin);
        }
        return buff[sp];
    }

public:
    InParser(const char* nume) {
        fin = fopen(nume, "r");
        buff = new char[4096]();
        sp = 4095;
    }

    InParser& operator >> (int &n) {
        char c;
        while (!isdigit(c = read_ch()) && c != '-');
        int sgn = 1;
        if (c == '-') {
            n = 0;
            sgn = -1;
        } else {
            n = c - '0';
        }
        while (isdigit(c = read_ch())) {
            n = 10 * n + c - '0';
        }
        n *= sgn;
        return *this;
    }

    InParser& operator >> (long long &n) {
        char c;
        n = 0;
        while (!isdigit(c = read_ch()) && c != '-');
        long long sgn = 1;
        if (c == '-') {
            n = 0;
            sgn = -1;
        } else {
            n = c - '0';
        }
        while (isdigit(c = read_ch())) {
            n = 10 * n + c - '0';
        }
        n *= sgn;
        return *this;
    }
};

InParser fi("triplete.in");
ofstream fo("triplete.out");
int n,m,i,A[65537],B[65537];
long long rez;
bitset<4096> P[4096];
bitset<4096> nr;
int main()
{
    fi>>n>>m;
    for(i=1; i<=m; i++)
    {
        fi>>A[i]>>B[i];
        A[i]--;
        B[i]--;
        P[A[i]][B[i]]=P[B[i]][A[i]]=1;
    }
    for(i=1; i<=m; i++)
    {
        nr=P[A[i]]&P[B[i]];
        rez=rez+nr.count();
    }
    fo<<rez/3<<"\n";
    fo.close();
    return 0;
}