#include <iostream>
#include <fstream>
#include <cmath>

using namespace std;

int rez, b, e, i, x=1;

int main () {
    
    ifstream fin("sumdiv.in");
    ofstream fout("sumdiv.out");
    
    fin >> b >> e;
    
    x = (pow(b,e+1)-1) / (b-1);
    fout << x % 9901;
}