Cod sursa(job #1870612)

Utilizator Marius7122FMI Ciltea Marian Marius7122 Data 6 februarie 2017 19:39:12
Problema Parantezare optima de matrici Scor 100
Compilator cpp Status done
Runda Arhiva educationala Marime 1.27 kb
#include <stdio.h>
#define maxn 505
long long inf = 1LL<<60;

int n,i,j,l,k;
long long d[maxn],inm[maxn][maxn],aux;          //inm[i][j] este costul inmultirii matricelor A(i)*A(i+1)*...*A(j)
                                            //A(i) are dimensiunea d[i-1]*d[i]


void afis()
{
    int i,j;
    for(i=1;i<=n;i++)
    {
        for(j=1;j<=n;j++)
            printf("%d ",inm[i][j]);
        printf("\n");
    }
    printf("\n");
}

int main()
{
    FILE *f1,*f2;
    f1=fopen("podm.in","r");
    f2=fopen("podm.out","w");

    fscanf(f1,"%d",&n);
    for(i=0;i<=n;i++)
        fscanf(f1,"%d",&d[i]);

    for(i=1;i<n;i++)                   //calculez costul inmultirii mat A(i) cu A(i+1) => l=1
        inm[i][i+1]=d[i-1]*d[i]*d[i+1];

    for(l=2;l<n;l++)                  //l este lungimea unei expresii
        for(i=1;i<=n-l;i++)
        {
            inm[i][i+l]=inf;
            for(j=0;j<l;j++)            //calculam costurile posibile si il alegem pe cel mai bun
            {
                k=j+i;
                aux=inm[i][k] + inm[k+1][i+l] + d[i-1]*d[k]*d[i+l];
                if(aux<inm[i][i+l])
                    inm[i][i+l]=aux;
            }
        }

    fprintf(f2,"%lld",inm[1][n]);



    //afis();

    return 0;
}