Pagini recente » Cod sursa (job #725537) | Cod sursa (job #3136589) | Cod sursa (job #382055) | Cod sursa (job #449992) | Cod sursa (job #1867560)
#include <cstdio>
#include <vector>
#include <cstring>
using namespace std;
vector <int> G[20005];
int U[20005],st[20005],dr[20005],sol;
int n,m,e,i,nr,x,y;
int cupleaza(int nod)
{
int i;
if (U[nod]) return 0;
U[nod]=1;
for (i=0; i<G[nod].size(); i++)
{
if (!dr[G[nod][i]] || cupleaza(dr[G[nod][i]]))
{
st[nod]=G[nod][i];
dr[G[nod][i]]=nod;
return 1;
}
}
return 0;
}
void cuplaj()
{
int i;
nr=1;
while (nr>0)
{
nr=0;
memset(U,0,sizeof(U));
for (i=1; i<=n; i++)
{
if (st[i]) continue;
if (cupleaza(i)) nr++;
}
}
}
int main()
{
freopen("cuplaj.in","r",stdin);
freopen("cuplaj.out","w",stdout);
scanf("%d %d %d",&n,&m,&e);
nr=0;
for (i=1; i<=e; i++)
{
scanf("%d %d",&x,&y);
G[x].push_back(y+n);
G[y+n].push_back(x);
}
cuplaj();
sol=0;
for (i=1; i<=n; i++) if (st[i]!=0) sol++;
printf("%d\n",sol);
for (i=1; i<=n; i++) if (st[i]!=0) printf("%d %d\n",i,st[i]-n);
return 0;
}