Pagini recente » Cod sursa (job #232691) | Cod sursa (job #1542856) | Cod sursa (job #334467) | locala | Cod sursa (job #1754880)
#include <cstdio>
#include <algorithm>
#define MOD 2000003
using namespace std;
int n,k,a[5002];
int main()
{
freopen("sandokan.in", "r", stdin);
freopen("sandokan.out", "w", stdout);
scanf("%d%d", &n, &k);
for(int i=1;i<=n;++i)
scanf("%d", &a[i]);
int m=n;
while(m>=k) m-=(k-1);
if(m<=1) {printf("1");return 0;}
//cel mai mare element nu poate fi eliminat
//el mereu va fi in sirul final
//in schimb folosindu-le de el putem elimina
//orice numar vrem
//deci trebuie sa calculam aranjari de
//(n-1)luate cate (k-1)
long long sol=1;--n;--m;
for(int i=n-m+1;i<=n;++i)
sol=(sol*i)%MOD;
printf("%d", sol);
return 0;
}