Borderou de evaluare (job #1710559)
Utilizator | Data | 29 mai 2016 11:59:12 | |
---|---|---|---|
Problema | Heavy metal | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp: In function ‘int main()’:
user.cpp:27:16: error: reference to ‘next’ is ambiguous
p=1;u=i;next=v[i].a;
^
user.cpp:15:17: note: candidates are: int next
int i,j,n,m,p,u,next;
^
In file included from /usr/include/c++/4.8/bits/stl_algobase.h:66:0,
from /usr/include/c++/4.8/bits/char_traits.h:39,
from /usr/include/c++/4.8/ios:40,
from /usr/include/c++/4.8/ostream:38,
from /usr/include/c++/4.8/iostream:39,
from user.cpp:1:
/usr/include/c++/4.8/bits/stl_iterator_base_funcs.h:184:5: note: template<class _ForwardIterator> _ForwardIterator std::next(_ForwardIterator, typename std::iterator_traits<_Iter>::difference_type)
next(_ForwardIterator __x, typename
^
user.cpp:31:23: error: reference to ‘next’ is ambiguous
if(v[m].b<=next) p=m+1;
^
user.cpp:15:17: note: candidates are: int next
int i,j,n,m,p,u,next;
^
In file included from /usr/include/c++/4.8/bits/stl_algobase.h:66:0,
from /usr/include/c++/4.8/bits/char_traits.h:39,
from /usr/include/c++/4.8/ios:40,
from /usr/include/c++/4.8/ostream:38,
from /usr/include/c++/4.8/iostream:39,
from user.cpp:1:
/usr/include/c++/4.8/bits/stl_iterator_base_funcs.h:184:5: note: template<class _ForwardIterator> _ForwardIterator std::next(_ForwardIterator, typename std::iterator_traits<_Iter>::difference_type)
next(_ForwardIterator __x, typename
^
user.cpp:35:18: error: reference to ‘next’ is ambiguous
if(v[m].b>next) m--;
^
user.cpp:15:17: note: candidates are: int next
int i,j,n,m,p,u,next;
^
In file included from /usr/include/c++/4.8/bits/stl_algobase.h:66:0,
from /usr/include/c++/4.8/bits/char_traits.h:39,
from /usr/include/c++/4.8/ios:40,
from /usr/include/c++/4.8/ostream:38,
from /usr/include/c++/4.8/iostream:39,
from user.cpp:1:
/usr/include/c++/4.8/bits/stl_iterator_base_funcs.h:184:5: note: template<class _ForwardIterator> _ForwardIterator std::next(_ForwardIterator, typename std::iterator_traits<_Iter>::difference_type)
next(_ForwardIterator __x, typename
^
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
- Daca tot nu e bine, contacteaza-ne pe forum !