Cod sursa(job #1709627)

Utilizator DobosDumitriuTUIASI AC Team 2016 bis DobosDumitriu Data 28 mai 2016 13:08:05
Problema Consecutive Scor 0
Compilator cpp Status done
Runda ONIS 2016 - Runda - 2 - ACM ICPC Romanian Programming Contest Marime 1.96 kb
#include <fstream>
#include <utility>
#include <vector>
#include <cmath>
#include <algorithm>
using namespace std;
vector<pair<int,int> > sol;
long z,nrsol=1,m,k,T,vmax,n,nrh;
pair<int,int> aux;
int main()
{
    ifstream fin("consecutive.in");
    ofstream fout("consecutive.out");
    fin>>T;
    for(int o=1; o<=T; o++)
    {
        fin>>n;
        z=sqrt(n);
        sol.clear();
        /*nrsol=0;
        if(n<=1000)
            for(int i=3; i<=n/2; i++)
            {
                if(n%i==0)
                {
                    if(n/i-i/2>0&&i%2==1)
                    {
                        sol.push_back(make_pair(n/i-i/2,n/i+i/2));
                        nrsol++;
                    }

                }
                if(i%2==0&&n%i==i/2&&n/i-i/2+1>0)
                    {
                        sol.push_back(make_pair(n/i-i/2+1,n/i+i/2));
                        nrsol++;
                    }
            }
        else*/
            for(int i=3; i<=n/2; i++)
            {
                if(n%i==0)
                {
                    if(n/i-i/2>0&&i%2==1)
                    {
                        sol.push_back(make_pair(n/i-i/2,n/i+i/2));
                        nrsol++;
                    }
                    if(n/(n/i)-(n/i)/2>0&&n/i!=i&&(n/i)%2==1)
                    {
                        sol.push_back(make_pair(n/(n/i)-(n/i)/2,n/( n/i)+(n/i)/2));
                        nrsol++;
                    }

                }
                if(i%2==0&&n%i==i/2&&n/i-i/2+1>0)
                    {
                        sol.push_back(make_pair(n/i-i/2+1,n/i+i/2));
                        nrsol++;
                    }
            }
        if(n%2==1&&n/2>0)
        {
            nrsol++;
        }
        fout<<nrsol<<'\n';
        if(n%2==1&&n/2>0)
        {
            fout<<n/2<<' '<<n/2+1<<'\n';
        }
        for(int i=0; i<sol.size(); i++)
        {
            fout<<sol[i].first<<' '<<sol[i].second<<'\n';
        }
    }
    return 0;
}