#include<iostream>
#include<fstream>
using namespace std;
int n,a[1000024];
long long countt,i;
long long  M = 19997;


int main(void){
  ifstream fin("twoton.in");
  ofstream fout("twoton.out");
  fin>>n;
  for(i=0;i<n;i++){
    fin>>a[i];
  }
   countt=1;
  if (n!=0){
      int minn=a[n-1];
      for(i=n-2;i>=0;i--){
	if(a[i]<minn){
	  countt=(countt+1)%M;
	}else{
	  countt=(2*countt+1)%M;
	}
      }
  }
  fout<<countt<<'\n';
  fout.close();
  fin.close();
  return 0;
}