Pagini recente » Cod sursa (job #3244183) | Cod sursa (job #1506021) | Cod sursa (job #859693) | Cod sursa (job #1143976) | Cod sursa (job #1691138)
#include <iostream>
#include <fstream>
#include <iomanip>
#define NMAX 3005
#define eps 0.00001
#include <cstdio>
using namespace std;
ifstream f("secv3.in");
int n,l,u,v[NMAX],t[NMAX],poz[NMAX];
double s[NMAX],Q[NMAX];
bool okay(double x)
{
int i,st=1,dr=0;
double maxim=-2000000000;
s[0]=0;
for(i=1;i<=n;++i)s[i]=s[i-1]+(1.0*v[i]-1.0*x*t[i]);
for(i=l;i<=n;++i)
{
while(st<=dr && poz[st]<i-u)++st;
while(st<=dr && Q[dr]>s[i-l])--dr;
++dr;Q[dr]=s[i-l];poz[dr]=i-l;
maxim=max(maxim,s[i]-s[poz[st]]);
}
return (maxim>=0);
}
void solve()
{
double st,dr,mij,sol=0; int i;
f>>n>>l>>u;
for(i=1;i<=n;i++)f>>v[i];
for(i=1;i<=n;i++)f>>t[i];
st=0; dr=2000;
while(st<dr+eps)
{
mij=(st+dr)/2;
if(okay(mij))
{
sol=mij;
st=mij+eps;
}
else
dr=mij-eps;
}
freopen("secv3.out","w",stdout);
printf("%.2lf\n", sol);
}
int main()
{
solve();
return 0;
}