Borderou de evaluare (job #1681174)

Utilizator razvanlgu31Razvan Lungu razvanlgu31 Data 9 aprilie 2016 12:04:26
Problema NN Status done
Runda Grigore Moisil 2016 Clasa a 10-a Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp:7:33: error: ‘long double y1’ redeclared as different kind of symbol long double d[100100],x,y,x1,x2,y1,y2; ^ In file included from /usr/include/features.h:357:0, from /usr/include/i386-linux-gnu/c++/4.8/bits/os_defines.h:39, from /usr/include/i386-linux-gnu/c++/4.8/bits/c++config.h:420, from /usr/include/c++/4.8/iosfwd:38, from /usr/include/c++/4.8/ios:38, from /usr/include/c++/4.8/istream:38, from /usr/include/c++/4.8/fstream:38, from user.cpp:1: /usr/include/i386-linux-gnu/bits/mathcalls.h:243:1: error: previous declaration of ‘double y1(double)’ __MATHCALL (y1,, (_Mdouble_)); ^ user.cpp: In function ‘int main()’: user.cpp:26:12: error: cannot bind ‘std::basic_istream<char>::__istream_type {aka std::basic_istream<char>}’ lvalue to ‘std::basic_istream<char>&&’ fin>>x1>>y1>>x2>>y2; ^ In file included from /usr/include/c++/4.8/fstream:38:0, from user.cpp:1: /usr/include/c++/4.8/istream:872:5: error: initializing argument 1 of ‘std::basic_istream<_CharT, _Traits>& std::operator>>(std::basic_istream<_CharT, _Traits>&&, _Tp&) [with _CharT = char; _Traits = std::char_traits<char>; _Tp = double(double)throw ()]’ operator>>(basic_istream<_CharT, _Traits>&& __is, _Tp& __x) ^ user.cpp:27:15: error: invalid operands of types ‘double(double)throw ()’ and ‘long double’ to binary ‘operator>’ if(y1>y2) ^ user.cpp:36:26: error: invalid operands of types ‘long double’ and ‘double(double)throw ()’ to binary ‘operator==’ if(d[mi]*x1==y1) ^ user.cpp:43:29: error: invalid operands of types ‘long double’ and ‘double(double)throw ()’ to binary ‘operator<’ if(d[mi]*x1<y1) ^ user.cpp:103:26: error: invalid operands of types ‘long double’ and ‘double(double)throw ()’ to binary ‘operator==’ if(d[mi]*x1==y1) ^ user.cpp:110:29: error: invalid operands of types ‘long double’ and ‘double(double)throw ()’ to binary ‘operator>’ if(d[mi]*x1>y1) ^

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