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Cod sursa(job #1650)
#include <fstream.h>
ifstream f("iepuri.in");
ofstream g("iepuri.out");
int a,b,c,x,y,z;
long n;
int ziua(long p)
{
if (p==0) return (x);
else if (p==1) return (y);
else if (p==2) return (z);
else { int tz;
tz=((ziua(p-1)*a)+(ziua(p-2)*b)+(ziua(p-3)*c))%666013;
return tz;
}
}
int main()
{
int t;
f>>t;
for (int i=1;i<=t;i++)
{
f>>x>>y>>z>>a>>b>>c>>n;
g<<ziua(n);
}
f.close();
g.close();
}