Borderou de evaluare (job #1635305)
Utilizator | Data | 6 martie 2016 16:36:30 | |
---|---|---|---|
Problema | Xor | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp:10:12: error: ‘int y1’ redeclared as different kind of symbol
int mod,x1,y1,x2,y2;
^
In file included from /usr/include/features.h:357:0,
from /usr/include/assert.h:37,
from /usr/include/c++/4.8/cassert:43,
from /usr/include/i386-linux-gnu/c++/4.8/bits/stdc++.h:33,
from user.cpp:1:
/usr/include/i386-linux-gnu/bits/mathcalls.h:243:1: error: previous declaration of ‘double y1(double)’
__MATHCALL (y1,, (_Mdouble_));
^
user.cpp: In function ‘int solve()’:
user.cpp:35:33: warning: pointer to a function used in arithmetic [-Wpointer-arith]
return (sum(x2,y2)-sum(x2,y1-1)-sum(x1-1,y2)+sum(x1-1,y1-1)+2*mod)%mod;
^
user.cpp:35:32: error: invalid conversion from ‘double (*)(double)throw ()’ to ‘int’ [-fpermissive]
return (sum(x2,y2)-sum(x2,y1-1)-sum(x1-1,y2)+sum(x1-1,y1-1)+2*mod)%mod;
^
user.cpp:21:5: error: initializing argument 2 of ‘int sum(int, int)’ [-fpermissive]
int sum(int x,int y)
^
user.cpp:35:61: warning: pointer to a function used in arithmetic [-Wpointer-arith]
return (sum(x2,y2)-sum(x2,y1-1)-sum(x1-1,y2)+sum(x1-1,y1-1)+2*mod)%mod;
^
user.cpp:35:60: error: invalid conversion from ‘double (*)(double)throw ()’ to ‘int’ [-fpermissive]
return (sum(x2,y2)-sum(x2,y1-1)-sum(x1-1,y2)+sum(x1-1,y1-1)+2*mod)%mod;
^
user.cpp:21:5: error: initializing argument 2 of ‘int sum(int, int)’ [-fpermissive]
int sum(int x,int y)
^
user.cpp: In function ‘int main()’:
user.cpp:44:12: error: cannot bind ‘std::basic_istream<char>::__istream_type {aka std::basic_istream<char>}’ lvalue to ‘std::basic_istream<char>&&’
fin>>x1>>y1>>x2>>y2;
^
In file included from /usr/include/c++/4.8/sstream:38:0,
from /usr/include/c++/4.8/complex:45,
from /usr/include/c++/4.8/ccomplex:38,
from /usr/include/i386-linux-gnu/c++/4.8/bits/stdc++.h:52,
from user.cpp:1:
/usr/include/c++/4.8/istream:872:5: error: initializing argument 1 of ‘std::basic_istream<_CharT, _Traits>& std::operator>>(std::basic_istream<_CharT, _Traits>&&, _Tp&) [with _CharT = char; _Traits = std::char_traits<char>; _Tp = double(double)throw ()]’
operator>>(basic_istream<_CharT, _Traits>&& __is, _Tp& __x)
^
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
- Daca tot nu e bine, contacteaza-ne pe forum !