#include <iostream>
#include <fstream>
#include <deque>
using namespace std;

int n, k, i, v[5000001], sum;
deque <int> d;
ifstream f("deque.in");
ofstream g("deque.out");

int main()
{f>>n>>k;
for(i=1; i<=n; ++i) f>>v[i];
for(i=1; i<=n; ++i)
{
    while(d.size() && v[d.back()]>=v[i]) d.pop_back();
    d.push_back(i);
    //cout<<v[d.front()]<<" ";
    if(d.front()==i-k)
      {sum=sum+v[d.front()];
       d.pop_front();}
}
g<<sum;
g.close();
f.close();
return 0;
}