#include <iostream>
#include <fstream>
#include <cmath>
using namespace std;
int main ()
{ 
  int i, j, n, t; char a[30000];
  ifstream f("cifra.in");
  ofstream g("cifra.out");
  f >> t;
  for (j = 1; j <= t; j++) {
    f >> a[j]; n = (int) a[j];
    int s = 0;
    for (i = 1; i <= n; i++)
      s += pow(i,i);
    g << s % 10 << endl;
  }
  f.close ();
  g.close ();
  return 0;
}