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// How about a coding trick?
#include <cstdio>
#include <algorithm>
#define DIM 100100
using namespace std;
FILE *fin=freopen("lupu.in","r",stdin);
FILE *fout=freopen("lupu.out","w",stdout);
struct type{
int T, lana;
};
int Heap[DIM];
type V[DIM];
int nr, n, x, l;
long long int sol;
inline int father(int nod)
{
return nod / 2;
}
inline int left_son(int nod)
{
return nod * 2;
}
inline int right_son(int nod)
{
return nod * 2 + 1;
}
inline void up(int nod)
{
int key = Heap[nod];
while( nod > 1 && (Heap[father(nod)] < key) )
{
Heap[nod] = Heap[father(nod)];
nod = father(nod);
}
Heap[nod] = key;
}
inline void down(int nod)
{
int son = 1;
while( son )
{
son = 0;
if( left_son(nod) <= nr )
{
son = left_son(nod);
if( right_son(nod) <= nr && Heap[right_son(nod)] > Heap[left_son(nod)] )
son = right_son(nod);
if( Heap[son] < Heap[nod] )
son = 0;
}
if( son )
{
swap( Heap[nod], Heap[son] );
nod = son;
}
}
}
inline bool comp(type a, type b)
{
return a.T < b.T;
}
void Read()
{
int i, d, a;
scanf("%d%d%d", &n, &x, &l);
if( !l )
{
for(int i = 1; i <= n; ++i)
{
scanf("%d%d", &d, &a);
if( d <= x )
sol += 1LL * a;
}
return;
}
for(i = 1; i <= n; ++i)
{
scanf("%d%d", &d, &a);
V[i].T = (x - d) / l;
V[i].lana = a;
}
sort(V + 1, V + n + 1, comp);
}
inline void Add(int val)
{
Heap[++nr] = val;
up( nr );
}
inline void Extract()
{
if( nr <= 0 )
return;
sol += 1LL * Heap[1];
Heap[1] = Heap[nr], --nr;
down( 1 );
}
void Solve()
{
int i, j;
if( !l )
{
printf("%lld", sol);
return;
}
V[0].T = -1;
for(i = n; i; --i)
{
j = i;
while( V[i].T == V[j].T && j )
{
Add(V[j].lana); --j;
}
i = j + 1;
for(j = 1; j <= V[i].T - V[i - 1].T; ++j)
Extract();
}
printf("%lld", sol);
}
int main()
{
Read();
Solve();
return 0;
}