#include <fstream>
#include <vector>
#include <queue>
using namespace std;
ifstream fin ("gather.in");
ofstream fout ("gather.out");
const int N = 755, P = 16, oo = 2e9;
priority_queue <pair <int, pair <int, int> >, vector <pair <int, pair <int, int> > >, greater <pair <int, pair <int, int> > > > H;
int d[P][N][P], n, m, k, det[N], nr[1 << P], z[P], dp[P][1 << P];
vector <pair <int, pair <int, int> > > g[N];
void dijkstra(int s) {
d[s][z[s]][k] = 0;
H.push(make_pair (0, make_pair (z[s], k)));
while (H.size()) {
int crt = H.top().first, x = H.top().second.first, y = H.top().second.second;
H.pop();
if (crt > d[s][x][y])
continue;
for (vector <pair <int, pair <int, int> > > :: iterator it = g[x].begin(); it != g[x].end(); ++it)
if (crt + it -> second.first < d[s][it -> first][min(y, it -> second.second)]) {
d[s][it -> first][min(y, it -> second.second)] = crt + it -> second.first;
H.push(make_pair (d[s][it -> first][min(y, it -> second.second)], make_pair (it -> first, min(y, it -> second.second))));
}
}
int last = oo;
for (int i = 0; i < k; ++i) {
last = oo;
for (int j = k; j >= 0; --j) {
if (d[s][z[i]][j] != oo)
last = min(last, d[s][z[i]][j]);
d[s][z[i]][j] = min(d[s][z[i]][j], last);
}
}
last = oo;
for (int j = k; j >= 0; --j) {
if (d[s][1][j] != oo)
last = min(last, d[s][1][j]);
d[s][1][j] = min(d[s][1][j], last);
}
}
int main() {
fin >> k >> n >> m;
for (int i = 0; i < k; ++i)
fin >> z[i];
for (int i = 0; i < k; ++i)
for (int j = 0; j <= n; ++j)
for (int p = 0; p <= k; ++p)
d[i][j][p] = oo;
for (int i = 0; i < k; ++i)
for (int j = 0; j < (1 << k); ++j)
dp[i][j] = oo;
for (int x, y, mx, c; m; --m) {
fin >> x >> y >> c >> mx;
g[x].push_back(make_pair (y, make_pair(c, mx)));
g[y].push_back(make_pair (x, make_pair(c, mx)));
}
for (int i = 1; i < (1 << k); ++i)
for (int j = 0; j < k; ++j)
if (i & (1 << j))
nr[i]++;
for (int i = 0; i < k; ++i) {
dijkstra(i);
dp[i][0] = d[i][1][0];
}
return 0;
for (int i = 0; i < k; ++i)
H.push(make_pair (dp[i][0], make_pair(i, 0)));
while (H.size()) {
int crt = H.top().first, x = H.top().second.first, dt = H.top().second.second;
H.pop();
if (nr[dt] == k) {
fout << dp[x][dt];
return 0;
}
for (int i = 0; i < k; ++i)
if (!(dt & (1 << i)) && d[x][z[i]][nr[dt]] != oo && crt + d[x][z[i]][nr[dt]] * (nr[dt] + 1) < dp[i][dt | (1 << i)]) {
dp[i][dt | (1 << i)] = crt + d[x][z[i]][nr[dt]] * (nr[dt] + 1);
H.push(make_pair(dp[i][dt | (1 << i)], make_pair(i, (dt | (1 << i)))));
}
}
}