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Borderou de evaluare (job #1147968)
Raport evaluator
Compilare:
user.cpp: In function ‘int main()’:
user.cpp:45:22: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&n,&m);
^
user.cpp:45:22: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:47:19: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld",&val);poz=i;
^
user.cpp:53:28: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&poz,&val);
^
user.cpp:53:28: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:57:24: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&x,&y);
^
user.cpp:57:24: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:59:20: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
printf("%ld\n",s);
^
user.cpp:62:20: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld",&val);
^
user.cpp:64:20: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
printf("%ld\n",y);
^
Test |
Timp executie |
Memorie folosita |
Mesaj |
Punctaj/test |
1 | 0ms | 232kb | OK | 10 |
2 | 4ms | 240kb | OK | 10 |
3 | 12ms | 252kb | OK | 10 |
4 | 56ms | 344kb | OK | 10 |
5 | 148ms | 384kb | OK | 10 |
6 | 252ms | 496kb | OK | 10 |
7 | 256ms | 576kb | OK | 10 |
8 | Depăşit | 632kb | Time limit exceeded. | 0 |
9 | Depăşit | 632kb | Time limit exceeded. | 0 |
10 | Depăşit | 632kb | Time limit exceeded. | 0 |
Punctaj total | 70 |