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Borderou de evaluare (job #1147838)
Raport evaluator
Compilare:
user.cpp: In function ‘int main()’:
user.cpp:39:22: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&n,&m);
^
user.cpp:39:22: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:41:19: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld",&val);poz=i;update(1,1,n);
^
user.cpp:46:28: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&poz,&val);
^
user.cpp:46:28: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:50:24: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld%ld",&x,&y);
^
user.cpp:50:24: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 3 has type ‘int*’ [-Wformat=]
user.cpp:52:20: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
printf("%ld\n",s);
^
user.cpp:55:20: warning: format ‘%ld’ expects argument of type ‘long int*’, but argument 2 has type ‘int*’ [-Wformat=]
scanf("%ld",&val);
^
user.cpp:57:20: warning: format ‘%ld’ expects argument of type ‘long int’, but argument 2 has type ‘int’ [-Wformat=]
printf("%ld\n",y);
^
| Test |
Timp executie |
Memorie folosita |
Mesaj |
Punctaj/test |
| 1 | 0ms | 232kb | OK | 10 |
| 2 | 4ms | 240kb | OK | 10 |
| 3 | 16ms | 288kb | OK | 10 |
| 4 | 60ms | 488kb | OK | 10 |
| 5 | 148ms | 740kb | OK | 10 |
| 6 | 232ms | 740kb | OK | 10 |
| 7 | 32ms | Depăşit | Memory limit exceeded. | 0 |
| 8 | 40ms | Depăşit | Memory limit exceeded. | 0 |
| 9 | 36ms | Depăşit | Memory limit exceeded. | 0 |
| 10 | 36ms | Depăşit | Memory limit exceeded. | 0 |
| Punctaj total | 60 |