Pagini recente » Borderou de evaluare (job #526177) | Borderou de evaluare (job #2238667) | Borderou de evaluare (job #2353065) | Borderou de evaluare (job #2149919) | Cod sursa (job #1098421)
#include <cstdio>
using namespace std;
int r[20][100002],n,m,x,y,lg[100002],i,j,k;
int min(int a,int b)
{
if (a>b) return b;
return a;
}
int main()
{
freopen("rmq.in","r",stdin);
freopen("rmq.out","w",stdout);
scanf("%d %d",&n,&m);
for (i=1; i<=n; i++) scanf("%d",&r[0][i]);
lg[1]=0;
for (i=2; i<=n; i++) lg[i]=lg[i/2]+1;
for (i=1; i<=lg[n]; i++)
for (j=1; j<=n-(1<<(i-1)); j++)
r[i][j]=min(r[i-1][j],r[i-1][j+(1<<(i-1))]);
for (i=1; i<=m; i++)
{
scanf("%d %d",&x,&y);
k=lg[y-x+1];
printf("%d\n",min(r[k][x],r[k][y-(1<<k)+1]));
}
return 0;
}