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#include <fstream>
#include <iostream>
#include <vector>
#include <bitset>
#include <string.h>
#include <algorithm>
#include <iomanip>
#include <math.h>
#include <time.h>
#include <stdlib.h>
#include <set>
#include <map>
#include <string>
#include <queue>
#include <deque>
using namespace std;
const char infile[] = "iepuri.in";
const char outfile[] = "iepuri.out";
ofstream fout(outfile);
const int MAXN = 100005;
const int oo = 0x3f3f3f3f;
const int MOD = 666013;
typedef int Matrix[4][4];
typedef vector<int> Graph[MAXN];
typedef vector<int> :: iterator It;
const inline int min(const int &a, const int &b) { if( a > b ) return b; return a; }
const inline int max(const int &a, const int &b) { if( a < b ) return b; return a; }
const inline void Get_min(int &a, const int b) { if( a > b ) a = b; }
const inline void Get_max(int &a, const int b) { if( a < b ) a = b; }
int X, Y, Z, A, B, C;
class Scanner {
public:
Scanner(string file, int buffer_size = 32768):
buffer_size_(buffer_size) {
file_ = fopen(file.c_str(), "r");
buffer_ = new char[buffer_size];
pointer_ = buffer_ + buffer_size_;
}
Scanner& operator>>(int &object) {
object = 0;
while (next() < '0' or next() > '9')
advance();
while (next() >= '0' and next() <= '9') {
object = object * 10 + next() - '0';
advance();
}
return *this;
}
private:
char next() {
if (pointer_ == buffer_ + buffer_size_) {
pointer_ = buffer_;
fread(buffer_, 1, buffer_size_, file_);
}
return *pointer_;
}
void advance() {
++pointer_;
}
FILE *file_;
int buffer_size_;
char *buffer_, *pointer_;
};
Scanner fin(infile);
inline void Multiply(Matrix A, Matrix B) {
Matrix M;
memset(M, 0, sizeof(M));
for(int i = 1 ; i <= 3 ; ++ i)
for(int j = 1 ; j <= 3 ; ++ j)
for(int k = 1 ; k <= 3 ; ++ k)
M[i][j] = (M[i][j] + 1LL * A[i][k] * B[k][j]) % MOD;
memcpy(A, M, sizeof(M));
}
inline int lgPow(int N) {
Matrix Ans, I;
memset(Ans, 0, sizeof(Ans));
memset(I, 0, sizeof(I));
Ans[1][2] = Ans[2][3] = 1;
Ans[3][1] = C;
Ans[3][2] = B;
Ans[3][3] = A;
I[1][1] = 1;
I[2][2] = 1;
I[3][3] = 1;
for(; N ; N >>= 1) {
if(N & 1)
Multiply(I, Ans);
Multiply(Ans, Ans);
}
return (1LL * I[3][1] * X + 1LL * I[3][2] * Y + 1LL * I[3][3] * Z) % MOD;
}
int main() {
int N, T;
fin >> T;
for(int i = 1 ; i <= T ; ++ i) {
fin >> X >> Y >> Z >> A >> B >> C >> N;
fout << lgPow(N - 2) << '\n';
}
return 0;
}