Compilare: user.cpp: In function ‘int main()’: user.cpp:14:13: warning: array subscript has type ‘char’ [-Wchar-subscripts] nr[a]=nr[b]=nr[c]=0; ^ user.cpp:14:19: warning: array subscript has type ‘char’ [-Wchar-subscripts] nr[a]=nr[b]=nr[c]=0; ^ user.cpp:14:25: warning: array subscript has type ‘char’ [-Wchar-subscripts] nr[a]=nr[b]=nr[c]=0; ^ user.cpp:16:22: warning: format ‘%s’ expects argument of type ‘char*’, but argument 2 has type ‘char (*)[105]’ [-Wformat=] scanf("%s",&s); ^ user.cpp:18:20: warning: array subscript has type ‘char’ [-Wchar-subscripts] nr[s[i]]++; ^ user.cpp:19:18: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((nr[a]==n)||(nr[b]==n)||(nr[c]==n)) ^ user.cpp:19:30: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((nr[a]==n)||(nr[b]==n)||(nr[c]==n)) ^ user.cpp:19:42: warning: array subscript has type ‘char’ [-Wchar-subscripts] if ((nr[a]==n)||(nr[b]==n)||(nr[c]==n)) ^ user.cpp:23:23: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (((nr[a]&1)==(nr[b]&1)) && ((nr[a]&1)==(nr[c]&1))) ^ user.cpp:23:34: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (((nr[a]&1)==(nr[b]&1)) && ((nr[a]&1)==(nr[c]&1))) ^ user.cpp:23:49: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (((nr[a]&1)==(nr[b]&1)) && ((nr[a]&1)==(nr[c]&1))) ^ user.cpp:23:60: warning: array subscript has type ‘char’ [-Wchar-subscripts] if (((nr[a]&1)==(nr[b]&1)) && ((nr[a]&1)==(nr[c]&1))) ^