Cod sursa(job #1037895)
Utilizator | Data | 20 noiembrie 2013 20:42:00 | |
---|---|---|---|
Problema | Ridicare la putere in timp logaritmic | Scor | 0 |
Compilator | cpp | Status | done |
Runda | Arhiva educationala | Marime | 0.41 kb |
#include <iostream>
#include <stdio.h>
using namespace std;
long long pow(long long n,int p)
{
if(p==0)
return n;
n=(n*n);
p-=2;
pow(n,p);
}
int main()
{
int n,p;
freopen("lgput.in","r",stdin);
freopen("lgput.out","w",stdout);
cin>>n>>p;
if(p%2==0)
cout<<pow(n,p)%1999999973;
else
cout <<n*pow(n,p-1)%1999999973<< endl;
return 0;
}