Cod sursa(job #1019901)
| Utilizator | Data | 1 noiembrie 2013 09:46:02 | |
|---|---|---|---|
| Problema | Ridicare la putere in timp logaritmic | Scor | 100 |
| Compilator | cpp | Status | done |
| Runda | Arhiva educationala | Marime | 0.49 kb |
/*
~Keep it Simple!~
*/
#include <stdio.h>
long long n,p;
long long SimplePow(long long n,long long p)
{
long long put=1;
while(p)
{
if(p%2)
{
put = (n*put)%1999999973;
p--;
}
n= (n*n)%1999999973;
p/=2;
}
return put;
}
int main()
{
freopen("lgput.in","r",stdin);
freopen("lgput.out","w",stdout);
scanf("%lld%lld",&n,&p);
printf("%lld",SimplePow(n,p));
}
