Diferente pentru blog/meet-in-the-middle intre reviziile #46 si #45
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Diferente intre continut:
bq. Given n a prime number and p, q two integer numbers between 0 and n-1 find k such that p^k^ = q modulo n. This problem can be solved using the baby step, giant step algorithm which uses the meet in the middle trick.
We can write k=$isqrt(n)+j$
We can write !http://latex.codecogs.com/gif.latex?k%20=%20i[\sqrt{n}%20+%201]%20+%20j!
Notice that i <= sqrt(n) and j <= sqrt(n). Now our equality looks like this p^ (i ([sqrt(n)] + 1) + j) = q modulo n. We can divide by p^j and get p^(i[sqrt(n)] + 1) = qp^-j modulo n. Now the application of meet in the middle becomes obvious. We can brute force through the numbers on each side of the equality and find a match.
